🌡️ Newton's Law of Cooling

Study Exponential Temperature Decay and Heat Transfer

✅ FREE Experiment • 📊 Real-Time Graphs • 🎓 NEB Class 11 Physics

🎯 Introduction

Newton's Law of Cooling states that the rate of heat loss of a body is directly proportional to the difference in temperature between the body and its surroundings, provided the temperature difference is small. Mathematically, this leads to an exponential decay of temperature with time.

This experiment simulates a hot object (like a cup of coffee or hot water) cooling down to room temperature. You'll observe the temperature decrease over time, plot cooling curves, calculate the cooling constant (k), and verify the exponential nature of the cooling process. This principle is fundamental to understanding heat transfer in everyday situations.

🎯 Learning Objectives

Interactive Thermometer

Watch the mercury level drop as temperature decreases exponentially

Experiment Setup

Current Temperature
25.0°C
Stable
Time: 0.0 s

Temperature of hot object at start

Room/surrounding temperature

Higher k = faster cooling (depends on material & surface area)

Interval for recording observations

📊 Calculated Results

Initial Temp (T_i)
80.0
°C
Ambient Temp (T₀)
25.0
°C
Current Temp (T)
80.0
°C
Cooling Constant (k)
0.050
s⁻¹
Temperature Drop
0.0
°C
Time Elapsed
0.0
seconds

🧮 Newton's Law Formula

T(t) = T₀ + (T_i - T₀)e^(-kt)

Where: T(t) = temperature at time t, T₀ = ambient temperature, T_i = initial temperature, k = cooling constant, t = time

📋 Observation Table

S.No. Time (s) Temperature (°C) T - T₀ (°C) ln(T - T₀)
No observations recorded yet. Click "Record" to add readings

📊 Analysis Tips

Linear Verification: Plot ln(T - T₀) vs time. If Newton's Law holds, you'll get a straight line with slope = -k. The y-intercept gives ln(T_i - T₀).

📈 Cooling Curves

Exponential decay curve. Temperature asymptotically approaches ambient temperature.

Linear plot for verification. Slope = -k (cooling constant).

Rate of cooling (dT/dt) decreases as temperature approaches ambient.

📚 Theory & Concepts

Newton's Law of Cooling

Newton's Law of Cooling states that the rate of change of temperature of an object is proportional to the difference between its temperature and the ambient temperature:

dT/dt = -k(T - T₀)

Where:

Derivation of Temperature Formula

Solving the differential equation dT/dt = -k(T - T₀):

Step 1: Separate variables

dT/(T - T₀) = -k dt

Step 2: Integrate both sides

∫ dT/(T - T₀) = ∫ -k dt
ln(T - T₀) = -kt + C

Step 3: Solve for T

T - T₀ = e^(-kt + C) = e^C · e^(-kt)

Step 4: Apply initial condition (T = T_i at t = 0)

T_i - T₀ = e^C
Therefore: e^C = T_i - T₀

Final Formula:

T(t) = T₀ + (T_i - T₀)e^(-kt)

Understanding the Equation

Behavior at Different Times:

Cooling Constant (k)

The cooling constant k determines how fast an object cools. It depends on:

Calculating k from Data

Method 1: Using Two Temperature Readings

If we know T at two different times t₁ and t₂:

k = [ln(T₁ - T₀) - ln(T₂ - T₀)] / (t₂ - t₁)

Method 2: Linear Regression

Taking natural log of both sides:
ln(T - T₀) = ln(T_i - T₀) - kt

This is a linear equation (y = mx + c form) where:

Plot ln(T - T₀) vs t. The slope of the best-fit line gives -k.

Assumptions and Limitations

Half-Life Concept

The "half-life" is the time for temperature difference to reduce by half:

t_½ = ln(2)/k ≈ 0.693/k

🔬 Experimental Procedure

  1. Set the initial temperature (hot object temperature) using slider
  2. Set the ambient temperature (room temperature) using slider
  3. Adjust cooling constant k (depends on object properties)
  4. Set time interval for recording observations (e.g., 5 seconds)
  5. Click "Start Cooling" to begin the experiment
  6. Watch the thermometer mercury level drop in real-time
  7. Click "Record" at regular intervals to add data to the table
  8. Observe the temperature approaching ambient temperature asymptotically
  9. Switch between graph tabs to view different representations
  10. Verify exponential decay in Temperature vs Time graph
  11. Verify linear relationship in ln(T - T₀) vs Time graph
  12. Calculate cooling constant from the slope of linear graph
  13. Click "Reset" to try with different parameters

💡 Real-World Applications

⚠️ Precautions (For Real Experiments)

💬 Viva Questions & Answers

What is Newton's Law of Cooling?

Newton's Law of Cooling states that the rate of heat loss of a body is directly proportional to the difference in temperature between the body and its surroundings, provided the temperature difference is small. Mathematically: dT/dt = -k(T - T₀).

What is the formula for temperature as a function of time?

T(t) = T₀ + (T_i - T₀)e^(-kt), where T(t) is temperature at time t, T₀ is ambient temperature, T_i is initial temperature, and k is the cooling constant. This shows exponential decay toward ambient temperature.

What does the cooling constant k represent?

The cooling constant k characterizes how fast an object cools. Higher k means faster cooling. It depends on surface area, thermal conductivity, specific heat capacity, mass, and the surrounding medium. Units are typically s⁻¹ or min⁻¹.

How do you verify Newton's Law experimentally?

Plot ln(T - T₀) versus time. If Newton's Law holds, this plot will be a straight line. The slope of this line equals -k (negative of cooling constant). This linear relationship confirms the exponential decay predicted by the law.

Why does temperature approach ambient temperature asymptotically?

As T approaches T₀, the temperature difference (T - T₀) becomes smaller, so the cooling rate dT/dt = -k(T - T₀) also becomes smaller. The object continues cooling but at an ever-decreasing rate, theoretically never exactly reaching T₀ (but practically does).

What factors affect the cooling constant k?

k increases with: (1) Larger surface area, (2) Better thermal conductivity, (3) Lower specific heat capacity, (4) Smaller mass, (5) Air movement (convection), (6) Lower surrounding pressure. k = hA/(mc), where h is heat transfer coefficient, A is area, m is mass, c is specific heat.

What are the assumptions of Newton's Law of Cooling?

(1) Temperature difference is relatively small (typically < 100°C), (2) Ambient temperature is constant, (3) Object has uniform temperature throughout, (4) Heat loss is primarily by convection, not radiation, (5) No phase changes occur, (6) Object properties don't change with temperature.

How is Newton's Law used in forensic science?

Forensic scientists estimate time of death by measuring body temperature and using Newton's Law. Normal body temperature is 37°C. By measuring current body temperature and knowing ambient temperature, they can calculate time since death using T(t) = T₀ + (37 - T₀)e^(-kt), with known k for human bodies.

Why must the temperature difference be small?

For large temperature differences, radiation becomes significant (Stefan-Boltzmann Law: radiation ∝ T⁴). Newton's Law assumes convection dominates, which is valid when radiation is negligible. This occurs when temperature differences are relatively small (< 100°C approximately).

What is the half-life in cooling?

The half-life t_½ is the time required for the temperature difference (T - T₀) to reduce to half its initial value. It equals t_½ = ln(2)/k ≈ 0.693/k. Like radioactive decay, this half-life is constant regardless of initial temperature difference.

How does stirring affect cooling?

Stirring increases convection within the liquid, making temperature more uniform and bringing hotter liquid to the surface faster. This effectively increases k (cooling constant), making cooling faster. Without stirring, surface cools faster than interior, violating uniform temperature assumption.

Does Newton's Law apply to heating as well?

Yes, the same law applies to heating. If an object is cooler than surroundings, it warms up following: T(t) = T₀ + (T_i - T₀)e^(-kt). Here, if T_i < T₀, the object temperature increases exponentially toward T₀. The same constant k applies for both heating and cooling.

What is the physical meaning of dT/dt = -k(T - T₀)?

dT/dt is the rate of temperature change. The negative sign means temperature decreases (for cooling). The proportionality to (T - T₀) means cooling rate is faster when the temperature difference is larger. When T = T₀, dT/dt = 0 (no more cooling).

How does surface area affect cooling?

Larger surface area increases heat loss rate, increasing k. A flat, spread-out object cools faster than a compact sphere of the same volume. This is why elephants have large ears (increase surface area for cooling) and why radiators have fins.

What happens if ambient temperature changes during experiment?

If T₀ changes, Newton's Law as stated doesn't apply accurately. The derivation assumes constant T₀. In practice, ensure room temperature stays constant by avoiding drafts, sunlight, and other heat sources. Small fluctuations (±1°C) are usually acceptable.